y=x^2 -4x -32. Use this function and identify the axis of symmetry and the vertex.

Question

Thank you.

Answer 1

By completing the square,
y=x^2-4x-32
=(x-2)²-4-32
=(x-2)²-36

The line x-2=0 passes through the vertex, hence the vertex is
(2,y(2))=(2, -36)

The line of symmetry of a parabola that opens up or down is the vertical line through the vertex.