Asked by Kesha

y=x^2+4x+11 can be written as y=(x+2)^2+7 by completing the square.Written this way one can that the function has a ____.
A.) minimum value of 7
B.) minimum value of -2
C.) minimum value of -2
D.) maximum value of 7

Answers

Answered by Steve
consider (x+2)^2
It is never negative, and is a minimum of zero when x = -2.

So, (x+2)^2+7 has its minimum of 7 when x = -2.

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