Y varies directly as the square of x and y=96 when x=4 find the value of y when x=5
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varies directly: y = kx^2
That means that y/x^2 = k, a constant.
So, you want y such that
y/5^2 = 96/4^2
That means that y/x^2 = k, a constant.
So, you want y such that
y/5^2 = 96/4^2
Value of y when X=24
Answer
y varies directly as the square of x and y=96 when x=4. Find the value of y when x=5
Value of the constant k