y(t) = -0.2451 cos 4t + 0.9804 sin 4t + e^(-3t ) (A cos⁡〖t+B〗 sin⁡〖t)〗

y'(t) = ?

1 answer

You are not being asked to solve a differential equation. You only have to take the derivative of the y(t) function you are given.

Just add the derivatives of the three separate terms.

The derivative of
-0.2451 cos(4t)
is
0.9804 sin(4t)

Your third term is illegible.