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y is partily a constant and partly varies as the square of x, if y=40 when x=1 and y =13 when x=2 find the value of y, when y=13

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When x=13, y=0.

y = mx^2+b
m+b = 40
4m+b = 13
solve for m and b, then
fix your typo to make it a real question.

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