y=cosxcosy-sinxsiny/sinxcosy+cosxsiny

Question

find dy/dx
plz show me working

Answer 1

I assume you meant:
y=(cosxcosy-sinxsiny)/(sinxcosy+cosxsiny)
= cos(x+y) / sin(x+y) , using your identities
= cot(x+y)

dy/dx = - csc^2 (x+y) (1 + dy/dx)
dy/dx = -csc^2 (x+y) - dy/dx csc^2 (x+y)
dy/dx + dy/dx csc^2 (x+y) = -csc^2 (x+y)
dy/dx(1 + csc^2 (x+y) ) = -csc^2 (x+y)
dy/dx = -csc^2 (x+y)/(1 + csc^2 (x+y) )

Answer 2

and, since y=cot(x+y),

dy/dx = -(y^2+1)/(y^2+2)