y = 2x^2+12x+14
y = 2(x^2+6x+9)-4
y = 2(x+3)^2-4
so, the vertex is at (-3,-4)
the y-intercept is at (0,14)
the x-intercepts are at (-3±√2,0)
y=a(x−h)^2+k and sketch its graph.
y=2x^2+12x+14
1 answer
y=2x^2+12x+14
1 answer