y=6-x y=x^2

Find the area of the region by
integrating with respect to x.

Find the area of the region by integrating with respect to y.
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i got the intersection pts to be(-3,9)and (2,4)....i then took the integral and found the answer to be 20.8333 for both parts...HOWEVER...its wrong! please help!

1 answer

Your intersection points are correct
Method1:
the effective height of a slice = 6-x - x^2

area = ∫ (6-x - x^2) dx from x = -3 to 2
= [6x - x^2/2 - x^3/3] from -3 to 2
= 12 - 2 - 8/3 - (-18 -9/2 - (-27/3) )
= 10 - 8/3 + 9 + 9/2
= 19 + 11/6
= 20 5/6 or 125/6 , so you were right
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