y
50
40
30
20
10
0
0
1
2
3
4
5
6
7
8
9
10
x
Write an equation in slope-intercept form of the trend line.
(1 point)
y =
7 answers
-10x + 50
That’s not right
Apologies for the earlier response. To find the equation in slope-intercept form of the trend line, we'll need to find the slope and y-intercept. Given the points (0, 50) and (10, 10), we can calculate:
Slope (m) = (y2 - y1) / (x2 - x1)
= (10 - 50) / (10 - 0)
= -40 / 10
= -4
Using the slope-intercept form (y = mx + b), we can substitute the slope (-4) and one of the points (0, 50) and solve for the y-intercept (b):
50 = -4(0) + b
50 = b
So, the equation in slope-intercept form of the trend line is:
y = -4x + 50
Slope (m) = (y2 - y1) / (x2 - x1)
= (10 - 50) / (10 - 0)
= -40 / 10
= -4
Using the slope-intercept form (y = mx + b), we can substitute the slope (-4) and one of the points (0, 50) and solve for the y-intercept (b):
50 = -4(0) + b
50 = b
So, the equation in slope-intercept form of the trend line is:
y = -4x + 50
STILL NOT RIGHT GIVE ME THE RIGHT ANSWER
Apologies for the confusion. Let's reevaluate the given points:
y: 50, 40, 30, 20, 10, 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
x: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16
Based on the given data points, it seems like there is a linear trend. Let's find the equation of the trend line using linear regression:
Step 1: Find the sum of x and y values.
Σx = 136
Σy = 180
Step 2: Find the sum of the products of x and y.
Σxy = 940
Step 3: Find the sum of x^2.
Σx^2 = 960
Step 4: Calculate the slope (m) and y-intercept (b) using the formulas:
m = (nΣxy - ΣxΣy) / (nΣx^2 - (Σx)^2)
b = (Σy - mΣx) / n
n = number of data points = 17
m = (17 * 940 - 136 * 180) / (17 * 960 - (136)^2)
= (15980 - 24480) / (16320 - 18496)
= -8500 / -216
m ≈ 39.352.
b = (180 - 39.352 * 136) / 17
= (180 - 5374.672) / 17
≈ 11.609.
Therefore, the equation of the trend line in slope-intercept form is:
y = 39.352x + 11.609.
y: 50, 40, 30, 20, 10, 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
x: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16
Based on the given data points, it seems like there is a linear trend. Let's find the equation of the trend line using linear regression:
Step 1: Find the sum of x and y values.
Σx = 136
Σy = 180
Step 2: Find the sum of the products of x and y.
Σxy = 940
Step 3: Find the sum of x^2.
Σx^2 = 960
Step 4: Calculate the slope (m) and y-intercept (b) using the formulas:
m = (nΣxy - ΣxΣy) / (nΣx^2 - (Σx)^2)
b = (Σy - mΣx) / n
n = number of data points = 17
m = (17 * 940 - 136 * 180) / (17 * 960 - (136)^2)
= (15980 - 24480) / (16320 - 18496)
= -8500 / -216
m ≈ 39.352.
b = (180 - 39.352 * 136) / 17
= (180 - 5374.672) / 17
≈ 11.609.
Therefore, the equation of the trend line in slope-intercept form is:
y = 39.352x + 11.609.
Give me the right answer NOW
Apologies for the confusion. Based on the given data points, the equation of the trend line in slope-intercept form is:
y = -2x + 50
y = -2x + 50