Y^5-12/y(z^2 -5) when y = 2 and z = 5

1 answer

To evaluate the expression \( \frac{y^5 - 12}{y(z^2 - 5)} \) when \( y = 2 \) and \( z = 5 \), we can substitute the values of \( y \) and \( z \) into the expression.

  1. Substitute \( y = 2 \) and \( z = 5 \):

\[ \text{Expression} = \frac{2^5 - 12}{2(5^2 - 5)} \]

  1. Calculate \( 2^5 \):

\[ 2^5 = 32 \]

  1. Now, substitute this back into the expression:

\[ = \frac{32 - 12}{2(5^2 - 5)} \]

  1. Simplify \( 32 - 12 \):

\[ = \frac{20}{2(5^2 - 5)} \]

  1. Now calculate \( 5^2 - 5 \):

\[ 5^2 = 25 \quad \Rightarrow \quad 25 - 5 = 20 \]

  1. Substitute this back into the expression:

\[ = \frac{20}{2(20)} \]

  1. Calculate \( 2(20) \):

\[ = 40 \]

  1. Now, substitute this into the expression:

\[ = \frac{20}{40} \]

  1. Simplify \( \frac{20}{40} \):

\[ = \frac{1}{2} \]

Therefore, the final result is:

\[ \frac{1}{2} \]