To find the point located on the graph of the equation y + 4 = -5(x - 3), we need to solve the equation for the variables x and y. Rearranging the equation, we get:
y + 4 = -5(x - 3)
y + 4 = -5x + 15
Now, we subtract 4 from both sides of the equation:
y = -5x + 15 - 4
y = -5x + 11
So, any point on the graph of this equation can be represented as (x, y) where y = -5x + 11.
As the equation is linear, any number we assign to x will give us a corresponding value of y that satisfies the equation. Let's examine a few points:
For x = 0, y = -5(0) + 11 = 11. So, one point on the graph is (0, 11).
For x = 2, y = -5(2) + 11 = 1. Another point on the graph is (2, 1).
For x = -3, y = -5(-3) + 11 = 26. Another point on the graph is (-3, 26).
Therefore, there are multiple points located on the graph of the equation y + 4 = -5(x - 3), such as (0, 11), (2, 1), (-3, 26), etc.
y+4=-5(x-3), what point is located here?
1 answer
1 answer