The given equations are:
y = 3x + 6 (equation 1)
y = -13x - 4 (equation 2)
We can solve this system of equations by equating the right side of both equations:
3x + 6 = -13x - 4
Now, let's solve for x:
3x + 13x = -4 - 6
16x = -10
Dividing both sides by 16:
x = -10/16
x = -5/8
Now, substitute the value of x back into one of the equations to find the value of y.
Using equation 1,
y = 3(-5/8) + 6
y = -15/8 + 48/8
y = 33/8
Therefore, the solution to the system of equations is x = -5/8 and y = 33/8.
y = 3x + 6 y = -13x - 4
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