y=−3x^2−4x+1

Question

(a) Write the equation of the parabola in standard form

it wants the answer like:
y= .....(x +-.....)^2...+-......

thank you

Answer 1

factoring ... y = -3 (x^2 + 4/3 x - 1/3)

completing the square ... y = -3 {[(x + 2/3)^2 - 4/9] - 1/3}

combining constants ... y = -3 (x + 2/3)^2 + 1/3

Answer 2

correction ... sorry

combining constants ... y = -3 (x + 2/3)^2 + 7/3

Answer 3

yes! thank you, Scott!!!!!!!!!!!!!!!!!!!!