y

Question

3
A (-1,2)
2
1
0
x
-2
-1
0
1
2.
3
4
5
-1
-2
B (4 ,- 2)
-3
Calculate midpoint M
of segment AB¯¯¯¯¯¯¯¯
.

(1 point)
Responses

M
is located at (1.5,0)
.
upper M is located at left parenthesis 1.5 comma 0 right parenthesis .

M
is located at (3,0)
.
upper M is located at left parenthesis 3 comma 0 right parenthesis .

M
is located at (0.5,1)
.
upper M is located at left parenthesis 0.5 comma 1 right parenthesis .

M
is located at (−2.5,2)
.
upper M is located at left parenthesis negative 2.5 comma 2 right parenthesis .

Answer 1

To find the midpoint \( M \) of the segment \( AB \), where \( A(-1, 2) \) and \( B(4, -2) \), we can use the midpoint formula:

\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]

Here, \( (x_1, y_1) = (-1, 2) \) and \( (x_2, y_2) = (4, -2) \).

Calculating the \( x \)-coordinate of the midpoint:

\[ x_M = \frac{-1 + 4}{2} = \frac{3}{2} = 1.5 \]

Calculating the \( y \)-coordinate of the midpoint:

\[ y_M = \frac{2 + (-2)}{2} = \frac{0}{2} = 0 \]

Therefore, the midpoint \( M \) of segment \( AB \) is:

\[ M = (1.5, 0) \]

So, the correct response is:

M is located at (1.5, 0).