y=[(3-4x)^(2/3)]/[(x^2+8)^(1/3)*(7+4x^3)^2]

Answer 1

x in (-oo:+oo)

x^2+(3/4)*x+1/8 = 0

x^2+3/4*x+1/8 = 0

DELTA = (3/4)^2-(1/8*1*4)

DELTA = 1/16

DELTA > 0

x = ((1/16)^(1/2)-3/4)/(1*2) or x = (-(1/16)^(1/2)-3/4)/(1*2)

x = -1/4 or x = -1/2

x in { -1/2, -1/4 }