y′=(2y+x)/x, y(1)=4

1. The resulting differential equation in x and u can be written as xu'=------

2.Separating variables we arrive at -----du= dx/x

3.Integrating both sides and simplifying, the solution can be written in the form u+1=Cf(x)
where C is an arbitrary constant and f(x)=-----

4.Transforming back into the variables x and y and using the initial condition to find C we find the explicit solution of the initial value problem is y=------

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