To find the intersection of the two equations \( y = 2x + 3 \) and \( y = 12x + 6 \), we can set the two equations equal to each other since they both equal \( y \):
\[ 2x + 3 = 12x + 6 \]
Now, let's solve for \( x \):
- Subtract \( 2x \) from both sides: \[ 3 = 10x + 6 \]
- Subtract 6 from both sides: \[ -3 = 10x \]
- Divide by 10: \[ x = -\frac{3}{10} \]
Now we find the corresponding \( y \) value by substituting \( x \) back into either of the original equations. We'll use the first equation \( y = 2x + 3 \):
\[ y = 2\left(-\frac{3}{10}\right) + 3 \] \[ y = -\frac{6}{10} + 3 \] \[ y = -\frac{6}{10} + \frac{30}{10} \] \[ y = \frac{24}{10} = \frac{12}{5} \]
Thus, the point of intersection is \( \left(-\frac{3}{10}, \frac{12}{5}\right) \).
None of the provided response options \( (2, 7) \), \( (2, -7) \), \( (7, 2) \), \( (-2, 7) \) match the intersection point. Therefore, please verify the equations or the options given.