y=2x^2-2x-3x+3 --> y = 2x^2 - 5x + 3 , so the first two are the same equation.
0 = 2x^2 - 3x - 2
are you subtracting this equation from the first?
then:
y-0 = 2x^2 - 2x^2 - 5x -(-3x) + 3-(-2)
y = -2x + 5
y=2x^2-2x-3x+3 y=2x^2-5x+3 0=2x^2-3x-2 when you minus this u get y=-2x-3x+5 how is this possible
3 answers
Why dint you multiply 2x^2 *-2x^2 as you have done with the others
At no point did I multiply anything
2x^2 - 2x^2 = 0 , that was a subtraction, just like 5-5 = 0
2x^2 - 2x^2 = 0 , that was a subtraction, just like 5-5 = 0
5 answers