If x = 0, then the term (x-120)^3 in the equation will be equal to (-120)^3 which is equal to -1728000, and therefore y will be equal to:
y = (25/216) (-1728000) + 200
y = -500 + 200
y = -300
So when x = 0, y will be equal to -300.
Similarly, if y = 0, then we can substitute 0 for y in the equation and solve for x:
0 = (25/216) (x-120)^3 + 200
-200 = (25/216) (x-120)^3
-8640 = (x-120)^3
x-120 = -20
x = 100
Therefore, when y = 0, x will be equal to 100.
So x and y do not both equal 0, but rather x = 100 and y = 0, or x = 0 and y = -300.
y=25/216 (x-120)^3+200
prove why x and y = 0 0
2 answers
AAAaannndd the bot gets it wrong yet again!
Not sure just what your question is, but if
y=25/216 (x-120)^3+200
then y is never zero
This is a parabola with vertex at (120,200) which opens upward.
Not sure just what your question is, but if
y=25/216 (x-120)^3+200
then y is never zero
This is a parabola with vertex at (120,200) which opens upward.