y^2 -20 y + 36 = 0
y = [ 20 +/- sqrt(400-144) ]/2
y = [20 +/- sqrt(256) ]/2
y = [ 20 +/- 16 ]/2
= 10 +/- 8
18 or 2
or
(y-2)(y-18) = 0
Y^2 - 20y + 100 = 64
Looking for exact solutions. I know they are integers, but...is there a decimal solution?
Thanks
5 answers
Marry me?
I doubt if you really want to marry a retired engineering professor who graduated from high school in 1955.
Yeah, it would be impossible to believe I'm near your age. I graduated in 1960..we never stop learning sir..
Thank you...
Thank you...
You are welcome :)