Y^2 - 20y + 100 = 64

Question

Looking for exact solutions. I know they are integers, but...is there a decimal solution?

Thanks

Answer 1

y^2 -20 y + 36 = 0

y = [ 20 +/- sqrt(400-144) ]/2

y = [20 +/- sqrt(256) ]/2

y = [ 20 +/- 16 ]/2

= 10 +/- 8

18 or 2

or
(y-2)(y-18) = 0

Answer 2

Marry me?

Answer 3

I doubt if you really want to marry a retired engineering professor who graduated from high school in 1955.

Answer 4

Yeah, it would be impossible to believe I'm near your age. I graduated in 1960..we never stop learning sir..

Thank you...

Answer 5

You are welcome :)