To factor the trinomial y^2 + 12y + 32, we need to find two numbers that multiply to 32 (the constant term) and add up to 12 (the coefficient of the middle term).
The two numbers are 8 and 4 because 8 * 4 = 32 and 8 + 4 = 12.
So, we can rewrite the trinomial as:
y^2 + 8y + 4y + 32
Now, we can factor by grouping:
y(y + 8) + 4(y + 8)
Factoring out the common factor from both terms, we get:
(y + 8)(y + 4)
Therefore, the factored form of y^2 + 12y + 32 is (y + 8)(y + 4).
y^2+12y+32
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