y

Question

104
9
8
7.
C (5,6)
6
-5
B (-4,3
4
3
2
1
1-04
-9 -8 -7 -6 -5 -4 -3 -2 -1,0 1 2 /3 4 5 6 7 8 9 10
-2-
D (2 ,- 2)
=3
-4-
-5-
A (-7 ,- 5)
-6
-- 7
-8.
-9
Suppose the parallelogram on the coordinate plane was dilated with respect to the origin using a magnitude of 12
. What would be the coordinates of vertex D′
?

(1 point)
(
,
)

Answer 1

To find the coordinates of vertex \( D' \) after dilating point \( D(2, -2) \) with respect to the origin by a factor of \( 12 \), you need to multiply both the \( x \) and \( y \) coordinates of point \( D \) by the dilation factor \( 12 \).

Starting with point \( D(2, -2) \):

\[ D' = (2 \times 12, -2 \times 12) \] \[ D' = (24, -24) \]

Therefore, the coordinates of vertex \( D' \) after the dilation would be:

\[ (24, -24) \]