Use the quadratic formula.
You be able to do work of this nature you MUST have learned how to solve a quadratic equation.
y=1.5 + 76.95t-(1/2)(9.8)t2 = 303.6
I am not sure how to arrive at this answer. I am confused because there is a t and a t^2. Thank you for your help!
5 answers
Yes but I always set it up incorrectly.
so [76.95 +/- sqrt (76.95^2 - 4(4.9)(-1.5)] / 9.8
Did I set this up correctly?
so [76.95 +/- sqrt (76.95^2 - 4(4.9)(-1.5)] / 9.8
Did I set this up correctly?
-4.9t^2 + 76.95t - 302.1 = 0
4.9t^2 - 76.95t + 302.1 =0
a=4.9
b=76.95
c=302.1
t = (76.95 ± √(76.95^2 - 4(4.9)(302.1))/9.8
see if you can get t = 18.856 or -3.252
what happened to your 303.6 in the opening equation?
4.9t^2 - 76.95t + 302.1 =0
a=4.9
b=76.95
c=302.1
t = (76.95 ± √(76.95^2 - 4(4.9)(302.1))/9.8
see if you can get t = 18.856 or -3.252
what happened to your 303.6 in the opening equation?
I was using this equation as an example to try to help myself understand something but I think I may have set it up incorrectly. What I am trying to do is find the y max of a projectile using the equation y = yo + (vo sin Q ) t -1/2gt^2.
I keep plugging in my values for the angles and vO but I cant seem to get y.
I keep plugging in my values for the angles and vO but I cant seem to get y.
Please disregard. Thank you.
1 answer