(y-1)/2u+x=m
(y-1)/2u=m-x
y-1=2u*(m-x) Divide with (m-x)
2u=(y-1)/(m-x) Divide with 2
u=(y-1)/[2*(m-x)]
(y-1)/2u+x=m what does "u" equal?
2 answers
1. multiply both sides by 2u+x
2.then multiply the m to (2u+x), so you should end up with y-1=2um+xm
3.then move the xm to the other side of the equation in order to isolate the u term, when you do this you should now have: y-1-xm=2um
4. then divide both sides by the 2m
and that should give you:
u=y-1-xm/2m
2.then multiply the m to (2u+x), so you should end up with y-1=2um+xm
3.then move the xm to the other side of the equation in order to isolate the u term, when you do this you should now have: y-1-xm=2um
4. then divide both sides by the 2m
and that should give you:
u=y-1-xm/2m