The equation you provided is a linear equation in slope-intercept form:
\[ y = mx + b \]
where \( m \) is the slope and \( b \) is the y-intercept.
In your original equation \( y = 0.14x + 3 \), the slope \( m \) is \( 0.14 \), and the y-intercept \( b \) is \( 3 \). This means that the line intersects the y-axis at the point (0, 3).
If you change the \( 3 \) to \( 0 \) in the equation, it becomes:
\[ y = 0.14x + 0 \] or simply \[ y = 0.14x \]
In this new equation, the slope remains the same at \( 0.14 \), but the y-intercept changes to \( 0 \). This means that the line will now intersect the y-axis at the origin (0, 0).
What happens to the graph:
- The slope of the line will remain the same (the line will still rise at the same angle).
- The line will shift downward so that it intersects the y-axis at (0, 0) instead of (0, 3).
In summary, the graph will be the same line with a lower vertical position, having moved down by 3 units.
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