The correct option is:
(2−0)2+(0−(−2))2√ and (2−(−1))2+(0−1)2√
This is the square root of the sum of the squares of the differences in the x and y coordinates of the points X, Y, and Z. This is the distance formula, and if any two of the distances are equal, then the triangle is isosceles.
△XYZ is given with X(2, 0), Y(0, −2), and Z(−1, 1). Which of the following can be used to prove that △XYZ is isosceles?(1 point)
Responses
(2−0)2+(0−(−2))2−−−−−−−−−−−−−−−−−−√ and (2−(−1))2+(0−1)2−−−−−−−−−−−−−−−−−−√
StartRoot left parenthesis 2 minus 0 right parenthesis squared plus left parenthesis 0 minus left parenthesis negative 2 right parenthesis right parenthesis squared EndRoot and StartRoot left parenthesis 2 minus left parenthesis negative 1 right parenthesis right parenthesis squared plus left parenthesis 0 minus 1 right parenthesis squared EndRoot
(0−(−1))2+(−2−1)2−−−−−−−−−−−−−−−−−−−√ and (2−0)2+(0−(−2))2−−−−−−−−−−−−−−−−−−√
StartRoot left parenthesis 0 minus left parenthesis negative 1 right parenthesis right parenthesis squared plus left parenthesis negative 2 minus 1 right parenthesis squared EndRoot and StartRoot left parenthesis 2 minus 0 right parenthesis squared plus left parenthesis 0 minus left parenthesis negative 2 right parenthesis right parenthesis squared EndRoot
(2−(−1))2+(0−1)2−−−−−−−−−−−−−−−−−−√ and (0−(−1))2+(−2−1)2−−−−−−−−−−−−−−−−−−−√
StartRoot left parenthesis 2 minus left parenthesis negative 1 right parenthesis right parenthesis squared plus left parenthesis 0 minus 1 right parenthesis squared EndRoot and StartRoot left parenthesis 0 minus left parenthesis negative 1 right parenthesis right parenthesis squared plus left parenthesis negative 2 minus 1 right parenthesis squared EndRoot
(0−(−1))2+(−2−1)2−−−−−−−−−−−−−−−−−−−√ and (−1−0)2+(1−(−2))2−−−−−−−−−−−−−−−−−−−√
1 answer