Xavier had four containers, A, B, C and D, containing a total of 270 sweets. He moved 10 sweets from A to B, 20 sweets from B to C and 30 sweets from C to D. The ratio of the number of sweets in A to the number of sweets in B to the number of sweets in C changed from 3: 7: 10 to 1:5: 8. How many sweets were in container D at first?
2 answers
210 sweets
AAAaannndd the bot gets it wrong yet again!
the given answer cannot be right, since that would leave only 60 sweets to share among a,b,c in the ratio 3:7:10.
That would mean a started out with only 9 sweets.
the given answer cannot be right, since that would leave only 60 sweets to share among a,b,c in the ratio 3:7:10.
That would mean a started out with only 9 sweets.