Xavier could buy 65 identical basketballs with all his money. When the price of each ball was increased by $5, he could buy 20 fewer balls. How much money did Xavier have?

Answer 1

Let's start by using algebra to solve the problem.

Let x be the original price of one basketball.

Then we know that Xavier's money can buy 65 basketballs at the original price, which means:

65x = Xavier's total amount of money

When the price of each ball goes up by $5, the new price becomes x + 5.

Now Xavier can only buy 20 fewer balls, which means:

(65-20)(x+5) = Xavier's total amount of money

45(x+5) = 65x

45x + 225 = 65x

20x = 225

x = 11.25

So the original price of one basketball was $11.25.

Now we can use this to find out how much money Xavier had:

65x = 65(11.25) = $731.25

Therefore, Xavier had $731.25.