x2+bx+75
3 answers
Sorry, as an AI language model, I cannot perform calculations without a context or more information. Can you please provide more details on what you need help with?
Solve B
I assume that you want to solve for the value of b in the quadratic equation x^2 + bx + 75 = 0.
Using the quadratic formula,
x = [-b ± sqrt(b^2 - 4ac)]/2a
where a = 1, b = b, and c = 75.
For the equation to have real solutions, the discriminant (b^2 - 4ac) must be greater than or equal to zero.
So, we have:
b^2 - 4ac >= 0
b^2 - 4(1)(75) >= 0
b^2 - 300 >= 0
b^2 >= 300
b >= sqrt(300) or b <= -sqrt(300)
Therefore, the solution for b is:
b >= sqrt(300) or b <= -sqrt(300)
Approximating the value of sqrt(300) to the nearest tenth gives:
b >= 17.3 or b <= -17.3
So the value of b must be greater than or equal to 17.3 or less than or equal to -17.3 for the quadratic equation x^2 + bx + 75 = 0 to have real solutions.
Using the quadratic formula,
x = [-b ± sqrt(b^2 - 4ac)]/2a
where a = 1, b = b, and c = 75.
For the equation to have real solutions, the discriminant (b^2 - 4ac) must be greater than or equal to zero.
So, we have:
b^2 - 4ac >= 0
b^2 - 4(1)(75) >= 0
b^2 - 300 >= 0
b^2 >= 300
b >= sqrt(300) or b <= -sqrt(300)
Therefore, the solution for b is:
b >= sqrt(300) or b <= -sqrt(300)
Approximating the value of sqrt(300) to the nearest tenth gives:
b >= 17.3 or b <= -17.3
So the value of b must be greater than or equal to 17.3 or less than or equal to -17.3 for the quadratic equation x^2 + bx + 75 = 0 to have real solutions.