X2_2x-8>o find the value of of x

Answer 1

Fixing your typos ....

x^2 - 2x - 8 > 0

(x-4)(x+2) > 0
If this were a function, we could see that it is
y = (x-4)(x+2) which would have zeros at 4 and -2

In effect we are looking at where the parabola lies above the x-axis

so it will be
x < -2 OR x > 4

You might have to put that in "interval notation"

proof:
https://www.wolframalpha.com/input/?i=y+%3D+%28x-4%29%28x%2B2%29