x2+22x +c find the value of c that makes the trinomial a perfect square
2 answers
c = 121
since (x+a)^2 = x2+2a+a^2, you want 2a = 22.
So, plug in a=11 and you have c = a^2 = 121
So, plug in a=11 and you have c = a^2 = 121