the rider/bike was already moving at X (like driving off a cliff)
so the Ek gain from the Ep loss is added to the initial Ek of the rider/bike
X
-
..-
…-
….-
……-
……….-
…………..-
………………-
…………………-
…………………..---------Y
-The loss of gravitational potential energy Ep of the rider and motorbike from X to Y is 4.66x10^4
-The kinetic energy Ek of the rider and motorbike at Y is 8.55x10^4.
Explain why the Ek of the rider and motorbike at Y is greater than the Ep of the rider and motorbike from X toY. Please explain in detail and clearly.
1 answer