x + y = and 2x + 3y = 7

1 answer

It seems there is a minor mistake in the first equation, as it appears incomplete. I will assume you intended to write a complete equation for \( x + y \).

If we proceed with the system of equations with the second equation given:

  1. \( x + y = c \) (where \( c \) is a constant)
  2. \( 2x + 3y = 7 \)

Without the value of \( c \), we cannot find specific values for \( x \) and \( y \). However, I can provide you with a general approach to solving it.

Step 1: Express \( y \) in terms of \( x \)

From the first equation, we can express \( y \) in terms of \( x \): \[ y = c - x \]

Step 2: Substitute into the second equation

Now substitute \( y = c - x \) into the second equation: \[ 2x + 3(c - x) = 7 \]

Step 3: Simplify the equation

Distributing \( 3 \) gives: \[ 2x + 3c - 3x = 7 \] Combining like terms: \[ -x + 3c = 7 \] Now isolate \( x \): \[ -x = 7 - 3c \] \[ x = 3c - 7 \]

Step 4: Find \( y \)

Now, substitute \( x \) back into the equation for \( y \): \[ y = c - (3c - 7) = c - 3c + 7 = 7 - 2c \]

Final Solution

Thus, we can express the solution as: \[ x = 3c - 7 \] \[ y = 7 - 2c \]

If you can provide a specific value for \( c \), we can determine specific values for \( x \) and \( y \). Alternatively, if you meant something else in the first equation, please clarify it!