3(X+Y=5XY)
3X+2Y=13XY
3X+3Y=15XY ------(1)
3X+2Y=13XY ------(2)
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SUBTRACT (1)-(2)
Y=2XY
CANCEL Y ON BOTH SIDES
=> 2X=1
=>X=1/2
FROM EQUATION --(1)
3Y=15XY-3X
3Y=3(5XY-X)
CANCEL 3
Y=5XY-X
=>5XY-Y=X
=>Y(5X-1)=X -----(3)
NOW SUBSTITUTE X IN EQUATION ----(3)
Y(5*(1/2)-1)=1/2
=>Y[(5/2)-1]=1/2
=>Y[2.5-1]=0.5
=>Y[1.5]=0.5
=>Y[3]=1
=>Y=1/3
THEREFORE X=1/2 & Y=1/3
X+Y=5XY,3X+2Y=13XY where x and y are not equl to 0
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