x y

4 1
8 2
12 3
16 4

Compare the table of Object A and the equation y = 15
x of Object B. Which of the two moving objects has greater speed and by what factor? (round to nearest hundredth)

1 answer

To determine the speed of each object, we need to calculate the ratio of the change in y (denoted as Δy) to the change in x (denoted as Δx).

For Object A:
Δy = 4 - 1 = 3
Δx = 16 - 4 = 12

For Object B:
Δy = 15 - 2 = 13
Δx = 8 - 4 = 4

Now we can calculate the speeds:
Speed of Object A = Δy/Δx = 3/12 = 0.25
Speed of Object B = Δy/Δx = 13/4 = 3.25

Comparing the speeds, we can see that Object B has a greater speed than Object A by a factor of 3.25/0.25 = 13.
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