x + y = 28

y = 2x - 5

y = Marci; x = Jennifer

Jennifer and Marci are selling cookies for a fundraiser. They sold 28 boxes of cookies together. Marci sold 5 less than twice the number that Jennifer sold. How many boxes of cookies did each girl sell? Use system of equations to solve the problem.

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1 answer

To solve this problem, we can use the system of equations given to represent the relationship between Jennifer and Marci's sales.

Let x represent the number of boxes Jennifer sold and y represent the number of boxes Marci sold.

The first equation given is x + y = 28. This equation represents the total number of boxes sold by both Jennifer and Marci.

The second equation given is y = 2x - 5. This equation represents the relationship between Marci's sales (y) and Jennifer's sales (x), with Marci selling 5 less than twice the number Jennifer sold.

To solve this system of equations, we can use substitution or elimination. Let's solve it using substitution.

We can start by substituting the expression for y from the second equation into the first equation:

x + (2x - 5) = 28.

Next, let's simplify the equation by combining like terms:

3x - 5 = 28.

Next, let's isolate the variable x by adding 5 to both sides of the equation:

3x = 33.

Finally, divide both sides of the equation by 3 to solve for x:

x = 11.

So, Jennifer sold 11 boxes of cookies.

To find the number of boxes Marci sold, we can substitute the value of x back into the second equation:

y = 2x - 5.

y = 2(11) - 5.

y = 22 - 5.

y = 17.

Therefore, Marci sold 17 boxes of cookies.

Jennifer sold 11 boxes of cookies and Marci sold 17 boxes of cookies.
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