X^x(root(x)=(xroot(x)^x???? Find x

Answer 1

I read that as:

(x^x)√x = x(√x^x)
square both sides

x^(2x)(x) = x^2(x^x)
x^(2x+1) = x^(x+2)

2x + 1 = x+2
x = 1

Answer 2

or,
(x^x)√x = x(√x^x)
divide by x^x
√x = x
x=1