y = x(x+4)^(2/3)
y' = (x+4)^(2/3) + 2x/3 * (x+4)^(-1/3)
= (5x+12)/(3(x+4)^(1/3))
y'' = 2(5x+24)/(9(x+4)^(4/3))
Since the denominator is always positive, we just need to look at the numerator.
inflection points where f '' = 0, x=-24/5
That's where it changes from concave down to concave up.
However, watch out for x = -4, where y' and y'' are undefined.
x(x+4)^(2/3)
a). Find the second derivative
b). Find any points of Inflection
c). Determine the intervals of Concavity
2 answers
1st deriv
= x(2/3)(x+4)^(-1/3) + (x+4)^(2/3)
= (1/3)(x+4)^(-1/3) [ 2x+ 3(x+4) ]
= (1/3)(5x+12)(x+4)^(-1/3)
2nd deriv
= (1/3)(5x+12)(-1/3)(x+4)^(-4/3) + (1/3)(5))x+4)^(-1/3)
= ....
= 2(5x+24)/(9(x+4)^(4/3) )
should be easy from there
= x(2/3)(x+4)^(-1/3) + (x+4)^(2/3)
= (1/3)(x+4)^(-1/3) [ 2x+ 3(x+4) ]
= (1/3)(5x+12)(x+4)^(-1/3)
2nd deriv
= (1/3)(5x+12)(-1/3)(x+4)^(-4/3) + (1/3)(5))x+4)^(-1/3)
= ....
= 2(5x+24)/(9(x+4)^(4/3) )
should be easy from there
2 answers