To determine how far the firework will travel before reaching the ground, we need to find the value of x that makes the equation 0=−25/36 x^2+16 2/3x true.
Let's substitute each value of x from the table into the equation and see which one makes it true.
For x = 36:
0 = -25/36 * 36^2 + 16 2/3 * 36
0 = -25/36 * 1296 + 16 2/3 * 36
0 = -900 + 600
0 ≠ -300
For x = 48:
0 = -25/36 * 48^2 + 16 2/3 * 48
0 = -25/36 * 2304 + 16 2/3 * 48
0 = -1600 + 800
0 ≠ -800
For x = 24:
0 = -25/36 * 24^2 + 16 2/3 * 24
0 = -25/36 * 576 + 16 2/3 * 24
0 = -400 + 400
0 = 0
For x = 12:
0 = -25/36 * 12^2 + 16 2/3 * 12
0 = -25/36 * 144 + 16 2/3 * 12
0 = -100 + 200
0 ≠ -100
Therefore, the only value of x in the table that makes the equation 0=−25/36 x^2+16 2/3x true is x = 24 feet.
x Substituted Evaluate True Statement? 12 24 36 48 When set off, a certain firework follows the path of the quadratic function h=−25/36 x^2+16 2/3x , where: h= the height of the firework in feet. x= the horizontal distance it travels in feet. To determine how far the firework will travel before reaching the ground, determine which value of x in table is a solution to the equation 0=−25/36 x^2+16 2/3x .
36 feet
48 feet
24 feet
12 feet
1 answer
1 answer