x square + 3x - 27=0

Answer 1

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

In this equation, a=1, b=3, and c=-27.

Plugging these values into the formula, we get:

x = (-3 ± √(3^2 - 4*1*(-27))) / 2*1
x = (-3 ± √(9 + 108)) / 2
x = (-3 ± √117) / 2
x = (-3 ± 10.82) / 2

Therefore, the solutions to the quadratic equation x^2 + 3x - 27 = 0 are:

x = (-3 + 10.82) / 2 or x = (-3 - 10.82) / 2
x = 7.82 / 2 or x = -13.82 / 2
x = 3.91 or x = -6.91

So the solutions are x = 3.91 and x = -6.91.