I will assume you meant ...
x^(log10 x = 100
then by definition:
logx 100 = log10x
changing to a common base of the log ...
log10 100/logx = logx/log1010
2/log10x = log10 x/1
(log10 x)^2 = 2
log10 x =√2
using my calculator
x = appr 25.9546 or x = appr .03853
(both answers can be verified)
x^(log10x)=100
I'm not sure how to do this at all...
1 answer