(x^3+y^3)(x^3-y^3)
(x^3+3x^2y+3xy^2+y^3)*(x^3-x^2y+3xy^2-y^3)
X ki power6 - y ki power 6 factorise
2 answers
ummm
(x^3+3x^2y+3xy^2+y^3) = (x+y)^3
(x^3+y^3)(x^3-y^3)
= (x+y)(x^2-xy+y^2) (x-y)(x^2+xy+y^2)
(x^3+3x^2y+3xy^2+y^3) = (x+y)^3
(x^3+y^3)(x^3-y^3)
= (x+y)(x^2-xy+y^2) (x-y)(x^2+xy+y^2)
0 answers