x = ky + m
2k+m=0
6k+m=20
k=5,m=-10
x = 5y-10
5*3-10 = 5
x is partly constant and partly varies as y, when y=2,x=0 and when y=6,x=20.find x when y=3
15 answers
10
K=5,M=-10 Wheny=3 x=5
the resistance R to the motion of a car is partly constant and partly varies as the square of the speed V. At 80km per hour the resistance is 1060N and 120km per hour, its resistance is 1460N. What will be the resistance at 140km per hour
I don't know the Answer to that question
R = ks^2+m
1060 = (80*80)k+m
6400k+m = 1060 ........(i)
1460 = (120*120)k+m
14400k+m = 1460 .........(ii)
Solve i and ii simultaneously and get k and m.
At 140km/h,
R = (140*140)k+m
Substitute for k and m and get the resistance at 140km/h
1060 = (80*80)k+m
6400k+m = 1060 ........(i)
1460 = (120*120)k+m
14400k+m = 1460 .........(ii)
Solve i and ii simultaneously and get k and m.
At 140km/h,
R = (140*140)k+m
Substitute for k and m and get the resistance at 140km/h
I have no idea
Can't really tell
I am sorry
I am sorry for using foul language
x is partly constant and partly varies as y. Express x in terms of y and constant h and k
How on earth is K = 5 , I don't get please adeola, explain
X is partly constant and partly varies as y when y=3,x=9andwhich y=5,x=13
I don't understand pls explain better
Find the difference between sands and d=120 when5=30findthe formula connecting dands