To determine the equation of the line that goes up 6 and to the left 1 place, we can interpret this as having a slope (m) and a y-intercept (b).
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Slope Calculation: The line goes "up 6" and "to the left 1," which gives a slope of: \[ m = \frac{\text{rise}}{\text{run}} = \frac{6}{-1} = -6 \]
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Equation Form: We can use the slope-intercept form of the equation of a line, which is \( y = mx + b \). Here, \( m = -6 \).
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Finding the y-intercept (b): If we assume the line starts at some point (x₀, y₀), we can use the slope to find other points. Without specific coordinates for where the line starts, we'll have to leave it as is or assume a point.
Let's say the line intercepts the y-axis at some point (0, b), then the equation is: \[ y = -6x + b \]
If there are specific points given (e.g., a point the line passes through), we could calculate \( b \) more precisely. Without additional details, you can assume \( b \) may be any y-intercept. The general equation you have based on the slope would still be: \[ y = -6x + b \] If you have specific points or more details to provide, I can help to find a specific value for \( b \) or further refine the equation!
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