n x = a n^2 + n + 2
a n^2+(1-x)n + 2 = 0
n= [ -a +/- sqrt (1-2x+x^2 -8a) ] / 2a
X= an+2/n+1
Make n the subject
3 answers
If your question means:
x = ( a n + 2 ) / ( n + 1 )
then
Multiply both sides by n + 1
x ( n + 1 ) = ( a n + 2 )
x n + x = a n + 2
Subtract x to both sides
x n = a n + 2 - x
Subttract a n to both sides
x n - a n = 2 - x
n ( x - a ) = 2 - x
Divide both sides by x - a
n = ( 2 - x ) / ( x - a )
Multiply numerator and denominator by - 1
x = ( x - 2 ) / ( a - x )
x = ( a n + 2 ) / ( n + 1 )
then
Multiply both sides by n + 1
x ( n + 1 ) = ( a n + 2 )
x n + x = a n + 2
Subtract x to both sides
x n = a n + 2 - x
Subttract a n to both sides
x n - a n = 2 - x
n ( x - a ) = 2 - x
Divide both sides by x - a
n = ( 2 - x ) / ( x - a )
Multiply numerator and denominator by - 1
x = ( x - 2 ) / ( a - x )
I make typo in last step.
The solution is:
n = ( x - 2 ) / ( a - x )
The solution is:
n = ( x - 2 ) / ( a - x )