X + ⅔ < 9, solve inequality..write as mixed number.

Answer 1

To solve the inequality \(X + \frac{2}{3} < 9\), follow these steps:

1. Isolate \(X\) by subtracting \(\frac{2}{3}\) from both sides of the inequality: \[ X < 9 - \frac{2}{3} \]

2. Convert 9 to a fraction with a denominator of 3: \[ 9 = \frac{27}{3} \]

3. Subtract the fractions: \[ X < \frac{27}{3} - \frac{2}{3} = \frac{27 - 2}{3} = \frac{25}{3} \]

4. Convert \(\frac{25}{3}\) to a mixed number:

   • Divide 25 by 3, which gives 8 with a remainder of 1.
   • Thus, \(\frac{25}{3} = 8 \frac{1}{3}\).

So the solution to the inequality is: \[ X < 8 \frac{1}{3} \]