|x+9| ≥ 0
x+9 ≥ 0 or -x-9 ≥ 0
x ≥ -9 or x ≤ -9
so x is any real number
We could have seen that from the start
|x+9| ≥ 0 by the very definition of the absolute value.
|anything| ≥ 0
|x+9| is greater than or equal to 0. Solve and graph the solution set on a number line.
3 answers
So would the set be (-9,�‡)?
The is 10/9