X²-9=0

X²+7=0
3x²=0
1/4x²-4=0
64b²=16
144-p²=0
5z²-45=0
H²=-49
5²-35=-35

1 answer

Solution:

X²-9=0 can be factored as (x+3)(x-3)=0. Therefore, x can be either 3 or -3.

X²+7=0 cannot be factored further using real numbers. Therefore, the solution is not a real number.

3x²=0 can be simplified to x²=0, which means x=0.

1/4x²-4=0 can be simplified to 1/4x²=4 or x²=16. The solutions are x=4 and x=-4.

64b²=16 can be simplified to 8b=±2 or b=±1/4.

144-p²=0 can be simplified to (12+p)(12-p)=0. Therefore, p can be either 12 or -12.

5z²-45=0 can be simplified to 5z²=45, which means z²=9. The solutions are z=3 and z=-3.

H²=-49 can be simplified to H=±7i, where i is the imaginary unit.

5²-35=-35 is not a valid equation.