x-8/x-9-x+1/x+9+x-17/x^2-81 =x^3-81x^2-7x-27/x^2.

Question

Can some check this my answer and see if it corre4ct please.

Answer 1

you appear to have completely ignored the order of operation, you must use brackets to show the expression in its proper way.
I will assume you meant

(x-8)/(x-9) - (x+1)/(x+9) + (x-17)/(x^2-81)

did you notice that x^2-81 = (x+9)(x-9), so x^2-81 is the LCD

then
(x-8)/(x-9) - (x+1)/(x+9) + (x-17)/(x^2-81)
=[(x-8)(x+9) - (x+1)(x-9) + x-17]/(x^2-81)
= [x^2+x-72 - (x^2-8x-9) + x-17]/(x^2-81)
= [x^2+x-72-x^2+8x-9+x-17]/(x^2-81)
= (10x-80)/(x^2-81)

check my steps, I tend to make stupid mistakes when typing and working out these questions at the same time

Answer 2

Thanks Reiny this is my first time and the operations was not in brackets so I DID NOT KNOW

Answer 3

No problem,
may people have difficulty writing fractions in this format, it is hard to create them

if you write x-8/x+9

it really means x - 8/x + 9 according to BEDMAS
so it is necessary to use brackets.