(x-8)^2+(y+3)^2=4

Question

put this into ​(xminus​h)squaredplus​(yminus​k)squaredequalsrsquared form

Answer 1

(x-8)^2 + (y+3)^2 = 4

(h = 8, k = -3, r = 2)

This equation in (x-h)^2 + (y-k)^2 = r^2 form is:

(x-8)^2 + (y-(-3))^2 = 2^2